big picture goals of the reu
Hoffman bound. For a finite graph $G$, $\chi(G) \ge \left\lceil 1 +\frac{\mu_1(G) }{-\mu_n(G) } \right\rceil$ (Spielman 19.3)
If $\mathcal G$ is a bounded-degree Borel pmp graph,
$$ \chi_\mu^\text{ap}(\mathcal G) \ge \left\lceil 1 +\frac{M(T_{\mathcal G}) }{-m(T_{\mathcal G}) } \right\rceil $$
where $T_\mathcal G$ is the adjacency operator for $\mathcal G$
$M$ and $m$ are “approximate eigenvalues”
$M(T_\mathcal G) = \max$ spectral value, $m(T_\mathcal G) = \min$ spectral value (Courant-Fischer)
$$ M(T_\mathcal G) = \sup_{ne 0} \frac{\lang T_\mathcal G f, f\rang}{\lang f, f\rang} $$
$\chi_\mu^\text{ap}$ is the approximate measurable chromatic number
Another result that may be extendable to infinite graphs: Nikiforov’s bound.
For a finite graph $G$, $\chi(G)\ge 1+\frac{\mu_1(G)}{\lambda_1(G) - \mu_1(G)}$.
Is there a descriptive version?
adjacency operator

<aside> <img src="/icons/pencil_yellow.svg" alt="/icons/pencil_yellow.svg" width="40px" />
Def. Let $\mathcal G$ be bounded-degree with $V(\mathcal G) = \R$ with Lebesgue measure $\mu$.
$$ L^2(\R)=\left\{ f:\R\to \mathbb C \mid
\int_\R |f(x)|^2 \ dx <\infty
\right\} $$
The adjacency operator of $\mathcal G$ is $T_\mathcal G:L^2(\R)\to L^2(\R)$ by
$$ \left(T_\mathcal G (f)\right)(x) = \sum_{y\sim x} f(y)
$$
</aside>
Claim. The image of $L^2(\R)$ under $T_\mathcal G$ is in $L^2(\R)$. Indeed, $T_\mathcal G$ is a bounded operator.
Proof:
Let $d$ bound the degrees of $\mathcal G$, i.e. $\sup_{v\in V} \deg(v) \le d$.
\left| \sum_{y\sim x} f(y) \right|^2
\le \deg(x)\cdot \sum_{y\sim x} \left| f(y) \right|^2
\le d\cdot \sum_{y\sim x} \left| f(y) \right|^2 $$
So indeed,
\int \left| \left(T_\mathcal G (f)\right)(x) \right|^2 \ dx \le
\int d\cdot \sum_{y\sim x} \left| f(y) \right|^2\ dx\\
=d\cdot \int \sum_{y\sim x} \left| f(x) \right|^2\ dx
\le \int d^2\cdot \left| f(x) \right|^2\ dx
= d^2\cdot \int \left| f(x) \right|^2\ dx
=d^2{\|f\|_2}^2 $$
mass transport step in this proof:
want to show: $\forall f\in L^2(\R)$
$$ \int \sum_{y\sim x} \left| f(y) \right|^2\ dx
= (\le ?) \int d\cdot \left| f(x) \right|^2\ dx
$$
let
$$ \varphi(x,y) = |f(x)|^2 $$
be our transport
we know that
\int \sum\limits_{y \sim x} \varphi(y,x) \ dx\\[4pt]
\int \sum\limits_{y \sim x} |f(y)|^2 \ dx $$